lim(x-> pi/4) (4sqrt2-(cosx+sinx)^5)/(1-sin2x)
Find the sum `(1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4)) - YouTube
Ifint(-pi/4)^((3pi)/4)(e^(pi/4)dx)/((e^x+e^(pi/4))(sinx+cosx))=kint(-pi/2)^( pi/2)secx dx , then the value of k is (a) 1/2 (b) 1/(sqrt(2)) (c) 1/(2sqrt(2)) (d) -1/(sqrt(2))
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Simplify (i) `(4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5))` (ii) `(1)/( sqrt(3) + - YouTube
![Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx](https://dwes9vv9u0550.cloudfront.net/images/12048498/4d707fbe-90ed-41ce-9139-c8b46daf2ff5.jpg "Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx")
Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx
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![SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12](https://cdn.numerade.com/ask_images/4150e8e2965a46589e6825184fa18722.jpg "SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12")
SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12
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Solved Python code Predicted output Actual output 2 + 3 3 * | Chegg.com
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