Let f(x) = sin (π/6 sin (π/2 sin x)) for all ∈ R and g (x) =π/2 sin x for all x ∈ R. Let (fog)(x) denote f(g(x) and (gof) (x)denote g(f(x)). -
Solve: sin^(-1)x=pi/6+cos^(-1)x
\sin(x%2B\frac{%CF%80}{6})dx&line2=\mathrm{Solution:\:}\frac{1}{4}(-\sin(2x%2B\frac{%CF%80}{6})%2B\sqrt{3}x)%2BC "What is the integral of sin(x)sin(x+pi/6) ?")
What is the integral of sin(x)sin(x+pi/6) ?
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Prove that sin (x - pi6 ) + cos (x - pi3 ) = √(3)sin x
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-\sin(x-\frac{%CF%80}{6})=\frac{1}{2}&line2=\mathrm{Solution:\:}x=\frac{%CF%80}{3}%2B2%CF%80n,x=\frac{5%CF%80}{3}%2B2%CF%80n "sin(x+pi/6)-sin(x-pi/6)= 1/2")
sin(x+pi/6)-sin(x-pi/6)= 1/2
find the range of function f(x)=sin(x+(pi)/(6))+cos(x-(pi)/(6))
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If sin ^-1x - cos ^-1x = pi/6 , then x is
Prove that sin (x - pi6 ) + cos (x - pi3 ) = √(3)sin x
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SOLVED: Rewrite sin(x+(π)/(6)) in terms of sin x and cos x. Enclose arguments of functions in parentheses. For example, sin (2 x) sin(x+(π)/(6 ))=
If y = |sin x|^|x| then what is the value of dy/dx at x=-pi/6?
%2B\cos(x)=\sin(x%2B%CF%80)&line2=\mathrm{Solution:\:}\mathrm{False} "prove sin(x-pi/6)+cos(x)=sin(x+pi)")
prove sin(x-pi/6)+cos(x)=sin(x+pi)
